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atoti.date_diff(from_date, to_date, /, *, unit=‘days’)

Return a measure equal to the difference between two dates. The measure evaluates to None if one of the dates is None.
  • Parameters:
    • from_date ( _DateConstantOrVariableMeasureConvertible) – The starting date.
    • to_date ( _DateConstantOrVariableMeasureConvertible) – The end date.
    • unit (Literal [ ‘seconds’ , ‘minutes’ , ‘hours’ , ‘days’ , ‘weeks’ , ‘months’ , ‘years’ ]) – The difference unit. Seconds, minutes, and hours are only allowed if the dates contain time information.
  • Return type: MeasureDefinition

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Example

>>> from datetime import date
>>> df = pd.DataFrame(
...     columns=["From", "To"],
...     data=[
...         (date(2020, 1, 1), date(2020, 1, 2)),
...         (date(2020, 2, 1), date(2020, 2, 21)),
...         (date(2020, 3, 20), None),
...         (date(2020, 5, 15), date(2020, 4, 15)),
...     ],
... )
>>> table = session.read_pandas(
...     df, default_values={"To": None}, table_name="Example"
... )
>>> cube = session.create_cube(table)
>>> l, m = cube.levels, cube.measures
>>> m["To"] = tt.agg.single_value(table["To"])
>>> m["Diff"] = tt.date_diff(l["From"], m["To"])
>>> cube.query(m["To"], m["Diff"], levels=[l["From"]], include_empty_rows=True)
                    To Diff
From
2020-01-01  2020-01-02    1
2020-02-01  2020-02-21   20
2020-03-20
2020-05-15  2020-04-15  -30